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The following is a Google translation of a Russian document by Kanarev.  This accompanies our Oct. 13, 2010 story: Kanarev announces a self-running motor-generator.


Kanarev FM, Zatsarinin SB


Announcement. Results Test-first model, the motor-generator - a simple and convincing proof of the falsity of the first law of Newton and current electrodynamics.


   Motor-generator MG-1 has the standard rotor and stator usual. The role of the motor he performs the rotor, and the role of the generator stator (Fig. 1). It took about 100 years to figure out how to get the generator rotor to rotate without external drive.



Fig. 1. Photos of the motor-generator MG-1


Testing the first model MG-1 began in early June 2010 and is still going on. Previously obtained results are presented in the article "Balance of power motor-generator, but to publish it in full until it is impossible, because it contains too much information, which is classified as trade secrets. Therefore, we will publish in summary form only fragments of this article.

   First of all, consider the balance of power MG-1 at idle. Theoretical structure of this balance is shown in Fig. 2.     


Fig. 2. Schedule changes the torque acting on the  rotor MG-1, when it started to work and uniform rotation


At the start of the rotor of its torque  overcomes the resistance in the form of moments of mechanical resistance and working  and in the form of the inertial moment . The sum of these resistances is  (Fig. 2). Once the rotor starts to rotate uniformly, then the inertial moment becomes positive  and resists the rotation of the rotor, and promotes its uniform rotation (Fig. 2). Uniform rotation of the rotor resist only the workload and the mechanical and aerodynamic resistance - . Waveforms of voltage and current at the beginning of the rotor is shown in Fig. 3. She recorded with resistance 0.1 ohms. This means that in one division waveform 0,5 / 0,1 = 5A.



Fig. 3. Oscillogram starting voltage and current excitation windings of the rotor with a flywheel


Amplitude of the first current pulse is more than 13 A. It is more than the average amplitude of almost 2 times and it is natural, since at this point the rotor resist not only the mechanical aspects But also the inertial moment  (Fig. 2). Analysis of the waveforms in Fig. 3, shows that the amplitudes of current pulses become equal after about 20 pulses. This means that the uniform rotation of the rotor begins after a 20-second pulse. Fig. 2, this time corresponds to point B. The amplitude of the first pulse voltage - 120V, and the amplitude of the first pulse current (Fig. 3) - 13A. This means that the power of the starting pulse is 120h13 = 1560 Tues But this power is taken from the primary energy source once, at the time of starting of the rotor into the work and therefore not included in the balance of power MG-1, which is implemented in many hours of work.

Since the inertial moment of the rotor is involved in the process of starting, it is necessary to know its value. To do this, first of all, to determine the kinetic energy of a uniformly rotating rotor and the mechanical power on its shaft.

   Relationship between the kinetic energy  uniformly moving body and its capacity  follows from the work done under his uniform motion in one second.




   Relationship between the kinetic energy  uniformly rotating body and its capacity  It also follows from the work done by them with a uniform rotation in one second




   Thus, the numerical value of the kinetic energy of a uniformly rotating rotor is equal to mechanical power on its shaft.

Physical essence we performed mathematical transformations (2) can be described briefly as follows. As the rotor rotates uniformly, to determine the mechanical power, hidden in his rotation, it must be the kinetic energy  divided into time . In every second of the rotational movement of the rotor does work, expressed in Joules (J). This means that its mechanical power is numerically equal to the kinetic energy divided by the second J / s = Watts. It is present on the rotor shaft during its rotation at a constant speed all the time. That presence has realized the value of the inertial moment .

Newton's first law, which implies that the uniform rectilinear motion of the body or its uniform rotation it is not acted upon by any forces or moments of forces, deny the existence of the inertial moment  on the rotor shaft in his uniform rotation. To see the error of Newton's first law, we define the magnitude of the inertial moment on the rotor shaft MG-1 if it has a flywheel, which increases the radius of gyration  rotor, and hence the time of its inertia .

   To compile the balance of power idling MG-1, we must note that the quantity of energy spent to overcome the inertial moment in the time of launch of the rotor is equal to the kinetic energy of its uniform rotation. To determine this energy, you need to know a lot of  rotor moment of inertia of its  and turnover .

Then the kinetic (mechanical), energy (power) of the rotor, rotating uniformly with n= 2000 rpm, is

.                  (3)


   We have calculated the value of shaft power uniformly rotating rotor is not recognized by the dynamics of Newton: on the shaft of a uniformly rotating rotor MH-1           = 2000ob/min. ever-present mechanical power, equal to 576.0 watts (3).

Voltage from the primary power source is fed into the excitation winding rotor MG-1 in the form of pulses, duration and amplitude can be adjusted over a wide range by changing the duty cycle. Fig. 4, as represented by voltage pulses of minimal duration, which has been achieved, while Fig. 4, b - Pulses with long duration.






Fig. 4. Oscillogram idling MG-1:

a) with a minimum pulse duration; b) With longer duration pulses


   The amplitude of voltage pulses (Fig. 4 a), filed with the excitation winding of the rotor is approximately equal to And their duty cycle - . Amplitude current pulses in the field winding of rotor is And their duty cycle - . With this in mind the average values of voltage and current are equal (Fig. 4, a):


;                                    (4)

.                                   (5)


   It is only natural that the average pulsed electric power applied to the excitation winding of the rotor is


.                                   (6)


   The oscillogram shown in Fig. 4, b, Voltage pulses long, and the shape of current pulses is not triangular. Duty cycle voltage And duty cycle current pulses . Amplitude voltage pulses are And current . With this in mind, their average values are ,  respectively, and the average pulse of electrical power equal to

.                             (7)


   However, modern textbooks on electrical engineering and electro consider the results of (6) and (7) is wrong and recommend sharing the product of the amplitudes of voltage pulses  and current    on duty cycle once.


.                                                    (8)


   Since all primary energy sources generate a continuous voltage, the power calculation, abstracted from their engine-generator must be conducted according to the formula (8).

But how to do it if duty cycle pulse voltage and current are different? No recommendations because the authors of such books unknown to the law of the formation of power in an electrical circuit. It reads: average power in any section of the circuit is the product of the average values of voltage and current (6), (7). Since the voltage is not pulsed and continuous, in determining the average power at the terminals of the meter we have in accordance with the law, the formation of power in the circuit do not have the right to divide a voltage at the duty cycle. The law permits us, in this case divided by duty cycle current only. Given this power at the terminals of the meter, which follows from the oscillograms in Fig. 4, and is equal to


.                                   (9)


   In the power supply of the rotor MG-1 filed no pulse and continuous voltage, so power (Fig. 4, b), Take away the power supply from the network, is




   How could mean power values calculated by formulas (9) and (10), and the value of capacity resulting from the disturbance on (Fig. 4 a) and (Fig. 4, b) And calculated by formulas (6) and (7)?.

If for multiplying the amplitude values of voltage and current, we divide by the duty cycle only the amplitude of current pulses, the physical essence of this action means that the voltage is applied to the rotor winding is not pulsed and continuous, which clearly contradicts the reality (Fig. 4) and the formation of power law in an electrical circuit. What to do? We must understand that the amount of pulsed power in different parts of the circuit is not equal to the power abstracted from the primary source of energy. Unusual result, but only in the recognition of his significant resolved all contradictions in the analysis of the balance of the pulsed power. Resolving these conflicts is dictated by the need to obtain the results of the analysis of energy processes in the consumer pulse energy, corresponding to reality, which checks consistency of consumed electricity with the energy of chemical reactions, for example, by electrolysis of water.

   Thus, the power, take away the power supply MG-1 from the primary energy source with a continuous voltage is equal to 33.0 W (9) and 48.68 W (10), and pulse power applied to the power supply to the excitation winding rotor, equal to 1, 90W (6) or 8.26 W (7).

Since the rotor rotates uniformly, then Newton's first law states that the sum of moments acting on it is zero. This means that a uniformly rotating rotor does not need  extra energy or power, to keep his uniform rotation, but the experiment has denied this. The rotor can rotate uniformly only if the filing unit to supply 33 watts or 48.68 watts of power from an external power source. The law of formation of power in the circuit makes clear that the power of 33 W (9) and 48.68 (10), served  the power supply is uniformly rotating rotor correspond to the continuous voltage at the terminals of the primary power source. In the excitation winding of the rotor and a pulse voltage and current, so the actual electric power applied to the rotor winding is equal to 1.9 W (6) and 8.26 W (7). This is closer to zero, corresponding to the first law of Newton, but not zero, which proves the inadequacy of the law.

Now let us analyze the physical essence of the implementation of pulsed power 1.9 W (6) and 8.26 W (7).

Fig. Two positive  inertial moment corresponds to the mechanical energy (power) of a uniformly rotating rotor. Power corresponding to this point is equal to 576.0 watts (3). This power is present on the rotor shaft is constantly at his uniform rotation. When the rotor winding fed voltage pulses with amplitudes:  or , Then at the same time a pulse currents with amplitudes  (Fig. 4 a). or 1.9 A (Fig. 4, b). The average values of these pulses are  (4)  (5) or and And their average   electrical power equal to 1.90 W (6) and 8.26 W (7). These are real electrical power pulses cast from the primary source of energy in the rotor winding. They added to the magnitude of inertial mechanical power 576.0 W (3), the constant presence on the rotor shaft when it is uniform rotation (Fig. 2). As a result of the constant inertial moment  receives a pulse increment  (Fig. 2), whose value corresponds to the pulse of electrical power  (6) or  (7). These increases are going to overcome the resistance That form the processes of generation of voltage and current in the rotor winding in the moments when its chain is closed (Fig. 2, intervals  and ). Once the rotor circuit is opened, these resistance disappear (Fig. 2, interval  or D...E), And the remaining stock of the inertial moment  continues to rotate the rotor to get them to the next pulse (Fig. 2, point ). From this it follows that the rotor picks up from the power pulses of electrical energy, average power is equal to 1.90 watts (6) or 8.26 W (7). Power is 33 W (9) and 48.68 W (10) does not correspond to the pulse voltage, a continuous voltage. Again, notice that the power of 33.0 W and 48.68 W corresponds to the average, continuously generated voltage network, but does not mean  pulsed voltage applied to the brush rotor motor-generator MG-1.

We reviewed the process of starting the rotor MG-1 and the process of uniform rotation at the minimum voltage pulse duration (Fig. 4 a) and we are surprised tiny quantity of electric power of 1.9 W (6), which rotates the rotor with a mass of uniformly 2,6 kg and a frequency of 2000 rpm. This is a surprise - a consequence of not accounting 576Vt power, the constant presence on the rotor shaft of MG-1, with its uniform rotation. This neglect is formed erroneous Newton's first law.

   Thus, the ever-present mechanical power of 576 watts per rotor shaft overcomes all kinds of permanent resistance to its rotation, and the pulses of electrical power 1.9 W (6) or 8.26 W (7) overcome recurring resistance in the formation of pulses of voltage and current in excitation winding rotor (Fig. 2, intervals .

And now pay attention to the narrow pulse (Fig. 4, b) SArising in the field winding of the rotor after the formation of the EMF pulse induction (Fig. 4, a ,b,c,d) And going down. This momentum back emf. In the stator windings and generates pulses of the emf induced and back emf. Pulses of power in the stator winding generates the load, so the parameters of the stator winding is taken so as to conform to the power needed to the consumer. As the main consumer of pulses output stator MG-1 was chosen as an electrolyzer. Since the electrolysis process takes place at high current, the stator winding has been formed for current pulses up to 100A at 12V voltage pulses. Planned to use these pulses for water electrolysis.

But the first test made their adjustments to the plan. Their essence was followed by the simplicity of the scheme of separation of pulses and the emf induced emf in the stator winding. She is allowed to use them separately. It was found that the pulse power induction, approximately 30% more power pulse self-induction, but the process of electrolysis of water is more intense when you connect the electrolyzer cell in the chain pulse emf stator. The reason is that the amplitude of the pulse amplitude of the emf emf pulse induction. Electrolytic cell, taking the pulses, automatically reduces their amplitude up to 2 volts, and accordingly increases the duration of the pulses. As a result, when using pulses of emf of their duty cycle in the cell becomes smaller pulse ratio EMF induction. This is the main reason for the energy effects resulting from the use of pulses of emf in the stator winding, which are not energy efficient, since they occur at the time of disconnection of supply voltage in the excitation winding rotor.

Take as an energy consumer, emf rotor single cell electrolyzer and lift the classical  first voltage and current at the terminals of the stator (Fig. 5, a), and after connecting the cell - at the terminals of the cell (Fig. 5, b).




a) pulses Emf

 in the stator

b) Are the same impulses EMF

self-inductance  in the cell

Fig. 5. Pulses of emf in the stator winding:

a) to enable the electrolyzer; b) After the electrolysis


   It is known that water electrolysis occurs at an average voltage of each cell is equal to about 2 volts. Why? It is not known. It is not known and the influence of the number of cells on the performance of the cell. The answer to this question was obtained recently, using self-rotating generator MG-1 to power the electrolyzer. It produces pulses of voltage (Fig. 5), which have no direct connection with the primary power source: battery or electric power grid. Amplitude and frequency of voltage pulses, which he claims to be, closely related to its structure and determined the frequency of its rotation. Fig. 5, as represented by waveforms EmfGenerated in the stator winding MG-1 at idle at break an electrical circuit that feeds the rotor winding, as in Fig. 5, b - Oscillogram of the same impulses in cell electrolyzer.

Quite naturally, to increase power pulses generated in the stator winding, had to increase the duration of the pulses in the rotor winding. As a result, electrical power pulses to the rotor shaft, calculated by formula (6)  increased to 26W. In this case, the circuit emf induced stator was included 20W bulb, and the circuit emf stator - a single cell electrolyzer. The processing of waveforms found that the average pulsed electric power at the terminals of the cell is 22 watts, and at the terminals of lamp - 4 watts. Their total value was equal to 26 watts at full incandescence lamps 20W, that is, the actual power in the stator winding was more power in the rotor winding is almost twice, unless you consider the energy produced gases: hydrogen and oxygen.

Video film of the MG-1 clearly demonstrates the intensity of the output of gases from one cell to cell. This intensity is equivalent to the intensity of the exit gases from the cell mass of gas-welding apparatus of LIGA-12, with the consumption of a network of more than 200 watts. This is much more electric power to the rotor shaft, obtained from the primary power source, but the old electrodynamics prohibits such a result.



From the experiments should be the main conclusion: when using the battery to power the field winding of rotor is one of the pulse voltage in the stator windings can be used for charging the battery, and another - on the process, such as water electrolysis. The result is an autonomous source of energy with a life equal to its lifetime. In assessing the energy efficiency of such a source of energy is lost meaning of "efficiency (efficiency), since such a power unit will serve about 5 years without requiring any other energy sources.




1. Kanarev FM Self-rotating generator (WWW.akademik.su).

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  • Feature: Nanotech / Electromagnetic > Kanarev >
    Kanarev critiques Nobel Prize in Physics - Russian Professor Ph. M. Kanarev presents facts about the thickness of graphene and the theoretical bensole molecule, concluding that the statement concerning the one-atom-thick carbon film is erroneous. A video he sent in an earlier email announced "the world's first self-rotating electric generator." (PESN; Oct. 13, 2010)

See also

Resources at PESWiki.com

Page posted by Sterling D. Allan Oct. 12, 2010
Last updated July 10, 2011



Scan Gauge II

Plugs in dashboard for instant mpg and other performance data.